the sum of radius of the …
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Sia ? 6 years, 6 months ago
Let the radius of the base and the height of the solid cylinder be r m and h m respectively.
Then r + h = 37 . . . (1) . . .[Given]
Total surface area of the solid cylinder = 1628 m2
⇒ 2{tex}\pi{/tex}r(h + r) = 1628
⇒ 2{tex}\pi{/tex}r(37) = 1628 . . . [Using (1)]
⇒ 2 × {tex}22\over7{/tex} × r × 37 = 1628
⇒ r = {tex}{{1628}\times7}\over2\times22\times37{/tex}
⇒ r = 7 m
Putting the value of r in (1), we get
7 + h = 37
⇒ h = 37 – 7 = 30 m
∴ Circumference of the base of the solid cylinder = 2{tex}\pi{/tex}r
= 2 ×{tex}22\over7{/tex}× 7 = 44 m
and volume of the cylinder = {tex}\pi{/tex}r2h
={tex}22\over7{/tex}× (7)2 × 30 = 4620 m3
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