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Derivations of equation of motion for …

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Derivations of equation of motion for uniform acceleration using graphical method

    • Posted by Darshan Kumar 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 7 answers

    Mr. Thakur 7 years, 2 months ago

    G haa....... YashRajpootThakur1 id se..... u can search me on it......

    0Thank You

    Nancy Rajput 7 years, 2 months ago

    hope its help you ☺

    0Thank You

    Nancy Rajput 7 years, 2 months ago

    for 3 equation ... => vbar=v+v0/2 and from 1 equation =>t =v-v0/a so =>x=vbar×t =(v+v0/2)(v-v0/a) =v^2-v0^2/2a =>2a(x)=v^2-v0^2

    0Thank You

    Nancy Rajput 7 years, 2 months ago

    for second equation , x = total area covered ... so .. x=area of reactangle+area of triangle ... => l×b+1/2base×height => v0×t+1/2(t)(v-v0) from 1 equation we get ....... => v0t+1/2(t)(atL => v0t+1/2at^2

    0Thank You

    Nancy Rajput 7 years, 2 months ago

    for 1 equation => a=v-v0/t => at=v-v0 => v=v0+at

    0Thank You

    Aman Kumar 7 years, 2 months ago

    Tum log brainly per ho??

    0Thank You

    Mr. Thakur 7 years, 2 months ago

    Arey yr.... yhaa pr kaise du answer..... Brianly app pr add kr question uss pr dunga yhaa nhi..... ho payega

    0Thank You

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