Find the area of sector of …
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Sia ? 6 years, 6 months ago
Given, {tex}\theta{/tex} = 30° and r = 4 cm
Area of sector OAPB ={tex}\frac { \theta } { 360 } \times \pi r ^ { 2 }{/tex}
Let 'A' be the area of corresponding major sector.
Then, A = Area of sector OAQB
{tex}\Rightarrow{/tex}A = Area of the circle - Area of the corresponding minor sector
{tex}\Rightarrow A = \pi r ^ { 2 } - \frac { \theta } { 360 } \times \pi r ^ { 2 }{/tex}
{tex}\Rightarrow A = \pi r ^ { 2 } \left( 1 - \frac { \theta } { 360 } \right){/tex}
{tex}\Rightarrow A = 3.14 \times 4 \times 4 \left( 1 - \frac { 30 } { 360 } \right) \mathrm { cm } ^ { 2 }{/tex}
{tex}\Rightarrow A = 3.14 \times 4 \times 4 \times \frac { 11 } { 12 } \mathrm { cm } ^ { 2 }{/tex}{tex}= \frac { 3.14 \times 44 } { 3 } \mathrm { cm } ^ { 2 }{/tex}= 46.05 cm2
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