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Two balls are thrown simultaneously .A vertically upwards with a speed of 20 m/s from ground and ,B vertically downwards from a height of 40 m with the same speed and along the same line At what point do the two balls collide above the ground

Posted by Abhishek Semwal 7 years, 2 months ago

CBSE > Class 11 > Physics

1 answers

Sheeja Menon 7 years, 2 months ago

1st case Vertically upwards Speed =20m/s Time=t Here acceleration is = -g Let us take the distance as 'x' m We know that s=ut + 1/2 at² By substituting the values, x=20×t+ 1/2× -g × t².............1 2nd case Vertically downwards Speed= 20m/s Time= t Acceleration = +g Distance =40-x From s=ut +1/2at² , 40-x=20×t +1/2gt².............2 Adding 1and 2 we get, 40=40t t=40/40=1 Substituting t=1 in equation 1 X=20+1/2×-9.8×1² =20-4.9 =15.1 m

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