If p^ th term of an …

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Sia ? 6 years, 6 months ago
q = a + (p - 1)d ..... (i)
p = a + (q - 1)d ...... (ii)
q - p = (p - 1 - q + 1)d
{tex}\frac{{q - p}}{{p - q}} = d{/tex}
{tex} \Rightarrow d = - 1{/tex}
Put the value of d in eq (i)
q = a + (p - 1) (-1)
{tex} \Rightarrow {/tex} q = a - p + 1
{tex} \Rightarrow {/tex} a = q + p - 1
ap+q = a +(p + q - 1)d
= (q + p - 1) + (p + q - 1) (-1)
= q + p - 1 - p - q + 1
= 0
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