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In a triangle abc de parallel …

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In a triangle abc de parallel to bc find the value of x

Posted by Furkhan Khan 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

As DE {tex}\parallel{/tex} BC
{tex}\therefore \frac{AD}{AB}=\frac{AE}{AC}{/tex}, {tex}{/tex}
.{tex}\frac{x}{2x+1}=\frac{x+3}{2x+8}{/tex}
(x + 3)(2x + 1) = x(2x + 8)
2x²+ x + 6x + 3 = 2x²+ 8x
3 = 8x - 7x
x = 3

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