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An object having a velocity 4.0m/s …

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An object having a velocity 4.0m/s is accelerated at the rate of 1.2m/s for5.0s . Find distance travelled during the period of acceleration

    • Posted by Abhay Kumar Pal 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Sparsh Wahi 7 years, 2 months ago

    Sol. Given u=4m/s , a = 1.2 m/s2 and time = 5 secs. Distance = s = ut + 1/2 at2 = 4(5)+1/2 (1.2)(5)2 =20 + 1/2 (1.2) (25) = 20 + 3 (5) = 35 m Ans.

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