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If 9x ^2+25y^2=181 and xy=-6 please …

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If 9x ^2+25y^2=181 and xy=-6 please find the value of 3x+5y.

    • Posted by Priyanshu Sharma 6 years, 7 months ago

    CBSE > Class 09 > Mathematics
    • 3 answers

    Chirag Goyal 6 years, 7 months ago

    (3x+5y)² =9x²+25y² +30xy (3x+5y)²=181 + 30*-6 (3x+5y)²=181-180 (3x+5y)²=1 3x+5y=1

    0Thank You

    Piyush Gupta 6 years, 7 months ago

    xy product can be 6 iff there are (1,6), (2,3),(3,2) or (6,1) as x and y soo by putting values of x,y in the equation we got (3,2 ) as solution But the condition is xy=-6 So x could be negative or y could be negative Hence there are two solutions of the eqn. 3x+5y , it could be (-3,2) or (3,-2) thats why we get different results as well for first solution we get 1 as the answer and -1 for the latter one. Therefore the equation would have positive or negative unity.

    2Thank You

    Priyanshu Sharma 6 years, 7 months ago

    Please give me my ans

    2Thank You

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