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in between two hills of height …

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in between two hills of height 100m & 92m respectively there is a value of breadth 16m the vehicle jumps from the first hill to the second what must be the minimum horizontal velocity so that it may not fall into the valley

  • 1 answers

Ankit Kumar 9 years ago

the above problem can be solved as

horizontal distance to be travelled is Sy 100 - 92= 8m

vertical distance to be travelled Sx = 16m

let vx be the horizontal velocity =constant here

now vertical sistance equation is Sy=ut+12 gt2

where u is vertical initial velocity

t is time taken to travel 8m i.e., reaching time to land second hill

as vertical initial velocity is 0

so above equation can be written as for time t,

 t=2XSyg

so t= 2x89.8 sec.

so t = 1.277 sec.

now taking horizontal distance as Sx= vx X t

16= vx X 1.277

on solving above we get minimum horizontal velocity required to land on second hill as Vx= 12.52 m/sec

 

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