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Find the point on the x-axis …

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Find the point on the x-axis which is equidistant from (2,-5) and (-2,9)

    • Posted by Dilpreet Singh 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Shavi Jasuja 7 years, 3 months ago

    X=8 chk your calculation

    0Thank You

    Yogita Ingle 7 years, 3 months ago

    Let the point of x-axis be P(x, 0)
    Given A(2, -5) and B(-2, 9) are equidistant from P
    That is PA = PB
    Hence PA2 = PB2  → (1)
    Distance between two points is √[(x2 - x1)2 + (y2 - y1)2]
    PA = √[(2 - x)2 + (-5 - 0)2]
    PA2 = 4 - 4x +x2 + 25 = x2 - 4x + 29
    Similarly, PB2 = x2 + 4x + 85
    Equation (1) becomes
    x2 - 4x + 29 = x2 + 4x + 85
    - 8x = 56
    x = -7
    Hence the point on x-axis is (-7, 0)

    5Thank You

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