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4x+ py+8=0

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4x+ py+8=0

Posted by Himani Kashyap 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Given linear equation is 4x + py + 8 = 0 and 2x + 2y + 2 = 0.
So, 4x + py + 8 = 0 ...(1)
and 2x + 2y + 2 = 0 ...(2)
a₁ = 4, b₁ = p, c₁ = 8, a₂= 2 , b₂ = 2 and c₂ = 2
The condition of unique solution, {tex}\frac { a _ { 1 } } { a _ { 2 } } \neq \frac { b _ { 1 } } { b _ { 2 } }{/tex}
Hence,{tex}\frac { 4 } { 2 } \neq \frac { p } { 2 } \text { or } \frac { 2 } { 1 } \neq \frac { p } { 2 }{/tex}
{tex}p \neq 4{/tex}

The value of p is other than 4 it may be 1,2,3, - 4 ,.... etc.

0Thank You

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