Find the distance of (-4,3) from …

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Sia ? 6 years, 6 months ago
The point on the y-axis is (-4,3)
{tex}\therefore {/tex}Distance between (-4,3) and (0,3)
d = {tex}\sqrt { ( 0 + 4 ) ^ { 2 } + ( 3 - 3 ) ^ { 2 } }{/tex}
= {tex}\sqrt { 16 + 0 }{/tex}
= 4 units
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