Is the point p(x,y) is equidistant …

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Sia ? 6 years, 6 months ago
The distances of P (x, y) from A (5,1) and B (-1,5) are equal, then we have to prove that 3x = 2y.
PA = PB
{tex}\therefore{/tex} PA2 = PB2
By distance formula,
(5 - x)2 + (1 - y)2= (-1 - x)2 + (5 - y)2
{tex}\Rightarrow{/tex}25 - 10x + x2 + 1 - 2y + y2 = 1 + 2x + x2 + 25 - 10y + y2
{tex}\Rightarrow{/tex} -10x - 2y = 2x - 10y
{tex}\Rightarrow{/tex} 8y = 12x
{tex}\Rightarrow{/tex}4(2y)= 4(3x)
{tex}\Rightarrow{/tex}3x = 2y
Hence Proved.
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