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The age of the father is twice the sum of the ages of children .after 20 years the age of father is equal to sum of age of tow children.find the age of father

Posted by Aswin Win 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Let father's age be x years and the sum of the ages of his two children be y years.
Then,
{tex}x = 2y{/tex}
{tex}\Rightarrow{/tex} {tex}x - 2y = 0{/tex} ....(i)
20 years hence,
Father's age = {tex}(x + 20) years{/tex}
Sum of the ages of two children {tex}= y + 20 + 20 = (y + 40) years{/tex}
Then, we have
{tex}x + 20 = y + 40{/tex}
{tex}\Rightarrow{/tex} {tex}x - y = 20 {/tex}....(ii)
Multiplying (ii) by 2, we get
{tex}2x - 2y = 40{/tex} ...(iii)
Subtracting (i) from (iii), we have
x = 40
Thus, the age of father is 40 years.

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