Prove work energy theorem?

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David Singh 8 years, 3 months ago
As per the defination of work:-
dW = Fdx
{tex}\int {/tex}dW ={tex}\int {/tex}Fdx
W=m{tex}\int {/tex}{tex}\frac{dv}{dt}{/tex} *dx (as F=ma and a=dv/dt)
W=m{tex}\int {/tex}v dv (as dx/dt=v)
W=m({tex}\left.\frac{v^2}{2}\right|_u^v{/tex})
W= {tex}\frac{mv^2}{2} - \frac{mu^2}{2}{/tex}
W=KE{tex}f{/tex} - KE{tex}i{/tex}
W={tex}\Delta {/tex}KE
3Thank You