Prove that : sec 8 theta-1/sec …
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Jatin Mann 7 years ago
sec8θ−1/sec4θ−1 =tan8θ/tan2θ
Or sec8θ−1/tan8θ=sec4θ−1/tan2θ
LHS
=1/cos8θ−1/sin8θ/cos8θ
=1−cos8θ/sin8θ
=2sin2(4θ)/2sin4θcos4θ
=tan4θ
RHS
=sec4θ−1/tan2θ
=1/cos4θ−1/tan2θ
=1−cos4θ/cos4θ(tan2θ)
=2sin2(2θ)cos4θ×sin2θcos2θ
=2sin2θcos2θcos4θ
=sin4θ/cos4θ
= tan4θ
= LHS
1Thank You