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Solve: Log2(X)+log4(X+2)=2

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Solve: Log2(X)+log4(X+2)=2
  • 1 answers

Aditya Wagh 7 years, 3 months ago

Log2(x)+log2(√x+2)=log2(4) Log2(x√x+2)=log2(4) Therefore, x^2(x+2)=16 X^3+2x^2-16=0 Solve this equation and u ll have ur answer But x should not be equal to 1,-2or 0
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