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1/a+b+c = 1/a + 1/b + …

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1/a+b+c = 1/a + 1/b + 1/ c
  • 1 answers

Chanchal Dhiman 7 years, 3 months ago

1/a+b+c=1/a+1/b+1/c =>1/a+b+c -1/c=1/a+1/b =>[c-(a+b+c)] /c(a+b+c) =(b+a) /ab =>Cross multiplying (since a, b, c=0 and a+b+c=0) =>c(a+b+c) (b+a) = -ab(a+b) =>(a+b) (ca+cb+cc+ab) =0 =>(a+b) (ca+cc+cb+ab) =0 =>(a+b) (b+c) (c+a) = 0 ?
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