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What is the compound interest of …

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What is the compound interest of p=18000 for 2.5years at 10% per annum
  • 1 answers

Sia ? 6 years, 4 months ago

By using year by year calculation
S.I. on Rs. 18000 at 10% per annum for 1 year
{tex} = \frac{{18000 \times 10 \times 1}}{{100}} = Rs.1800{/tex}
∴ Amount at the end of 1st year
= Rs. 18000 + Rs. 1800
= Rs. 19800
= Principle for 2nd year.
S.I. on Rs. 19800 at 10% per annum for 1 year
{tex} = \frac{{19800 \times 10 \times 1}}{{100}}{/tex}
= Rs. 1980
∴ Amount at the end of 2nd year
= Rs. 19800 + Rs. 1980
= Rs. 21780
= Principle for 3rd year
S.I. on Rs. 21780 at 10% per annum for {tex}\frac{1}{2}{/tex} year
{tex} = \frac{{21780 \times 10 \times 1}}{{2 \times 100}}{/tex}
= Rs. 1089
∴ Amount at the end of {tex}2\frac{1}{2}{/tex} years
= Rs. 21780 + Rs. 1089 
= Rs. 22869
this is the required amount.
Now,
C.I. = Rs. 22869 – Rs. 18000
= Rs. 4869.

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