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Chapter 4 exercise 4.2 Question number …

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Chapter 4 exercise 4.2 Question number 4 find two consecutive positive integers, sum of whose squares is 365.
  • 1 answers

Simran Samra 7 years, 3 months ago

Let numbers be x;x+1 (X)2+(x+1)2=365 X2+x2+1+2x=365 2x2+2x+1-365=0 2x2+2x-364=0 2(x2+x-182)=0 X2+x-182=0 X2-13x+14x-182=0 X(x-13)+14(x-13)=0 (X+14)(x-13)=0 X=-14;x=13 X=-14 rejected Other no. Is 13+1=14
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