Prove that if x and y …

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Sia ? 6 years, 4 months ago
Since x and y are odd positive integers, Then it should be in the form of 2x+1 (where x is a positive integer)
Let x = 2m + 1 and y = 2n + 1 ( where m and n positive integers)
Now x2 + y2
= (2m + 1)2 + (2n + 1)2
= 4m2 + 4m + 1 + 4n2 + 4n + 1
= 4(m2 + n2 + m + n) + 2 ....... (1)
from (1) we get
x2 + y2 = 2 {m2 + n2 + m + n) + 1} = 2t (t = 2(m2 + n2 + m + n) + 1 is a positive integer
Therefore it is clear that {tex}x^2+y^2{/tex} is an even number but not divisible by 4.
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