Use Euclid's division lemma to show …

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Sia ? 6 years, 4 months ago
Let n be any positive integer.
By Euclid's division lemma, n = 5q + r, 0{tex}\leqslant{/tex}r < 5
n = 5q,5q + 1,5q + 2 ,5q 4- 3 or 5q + 4, where q{tex}\in \omega{/tex}
Now we find the square of n
If n=5q then (5q)2 = 25q2= 5(5q2) = 5m
If n=5q+1then n2= (5q + 1 )2 = 25q2 + 10q + 1 = 5m + 1
If n=5q+2 then n2 = (5q + 2)2 = 25q2 + 20q + 4 = 5m + 4
If n=5q+4 then n2=(5q + 3)2=25q2+30q+9=5m + 1
Thus square of any positive integer is in the form of 5m,5m+1 or 5m+4, hence cannot be of the form 5m + 2 or 5m + 3.
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