Using Euclid division algorithm find the …
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Sia ? 5 years, 11 months ago
The given numbers are 1251,9377 and 15628
Subtracting the remainders 1,2 and 3 from 1251,9377 and 15628 respectively we get
1251 - 1 = 1250,
9377 - 2 = 9375
15628 - 3 = 15625.
Therefore the said number= HCF(1250,9375,15625)
Now on applying Euclid's lemma on 1250 and 9375 we get
9375 = 1250 × 7 + 625
1250 = 625 ×2+0
Hence HCF (1250 , 9375 )= 625.
Now on applying Euclid's lemma on 15625 and 625 we get
15625=625 × 25+0
Hence, HCF (1250, 9375,15265)= 625.
Thus, the said number = 625.
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