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Prove that sin3x+sin5x+sin7x+sin9x/cos3x+cos5x+cos7x+cos9x=tan6x

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Prove that sin3x+sin5x+sin7x+sin9x/cos3x+cos5x+cos7x+cos9x=tan6x

    • Posted by Ayush Pathak 7 years ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Ashish Kumar Singh 7 years ago

    We know that sinx+siny=2sinx+y/2•2cosx-y/2 and cosx+cosy=2cosx+y/2cosx-y/2 Taking 7x and 5x together and 3xand 9x 2sin6x.cosx+2sin6xcos3x/2cos6xcosx+2cos6xcos3x 2sin6x(cosx+3x)/2cos6x(cosx+cos3x) Cancelling cosx+3x Sin6x/cosx= tanx

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