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Solve :- (1+i)^6 +(1-i)^3

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Solve :- (1+i)^6 +(1-i)^3
  • 1 answers

Lav Kush Dixit 7 years, 4 months ago

[(1+i)^2]^3+(1-i)^3 (i^2=-1)(i^3=-i) [(1^2+i^2+2i)]^3+(1-i^3-3i+3i^2) [(1-1+2i)]^3+(1-i-3i-3) (2i)^3+(-2-4i) -8i-2-4i=( -12i-2) -2(6i+1) =6i+1
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