Find the points on the x-axis …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Test
Related Questions
Posted by Lakshay Kumar 1 year, 1 month ago
- 0 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 1 answers
Posted by Vanshika Bhatnagar 1 year, 4 months ago
- 2 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 0 answers
Posted by Sahil Sahil 1 year, 4 months ago
- 2 answers
Posted by Hari Anand 6 months, 1 week ago
- 0 answers
Posted by Kanika . 1 month ago
- 1 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 6 years, 4 months ago
We have to find the points on X-axis which are at a distance of {tex}2\sqrt5{/tex} from the point(7,-4). Also,we will how many such points are there.
Let, the point on X-axis be (x,0).
Now, by using distance formula,
{tex}\sqrt{(x_{2\;}-\;x_1)^2+\;(y_2-\;y_2)^2} {/tex}
{tex}\sqrt{(x-7)^2+(0+4)^2}= 2\sqrt5{/tex}
Squaring both sides,
{tex}\Rightarrow (x-7)^2+4^2=(2\sqrt5)^2{/tex}
{tex}\Rightarrow x^2 - 14x + 49 + 16 = 20{/tex}
{tex}\Rightarrow x^2-14x+45=0{/tex}
{tex}\Rightarrow {/tex} (x - 9) (x - 5) = 0
{tex}\Rightarrow x=9 \;or\;x=5{/tex}
Hence, two points exists (9,0) and (5,0)
0Thank You