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Tan2x tanx/tan2x - tanx = sin2x

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Tan2x tanx/tan2x - tanx = sin2x
  • 1 answers

Pratham Patel 5 years, 3 months ago

L.H.S.=tan2x.tanxtan2x−tanx=sin2xcos2x.sinxcosxsin2xcos2x−sinxcosx=sin2xcos2x.sinxcosxsin2x.cosx−cos2x.sinxcos2x.cosx=sin2x.sinxsin2x.cosx−cos2x.sinxUsing idenity :sin(A−B)=sinA.cosB−cosA.sinB,we get,L.H.S.=sin2x.sinxsin(2x−x)=sin2x.sinxsinx⇒L.H.S.=sin2x=R.H.S. (Hence proved)
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