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Cos(22/7/4-x) cos22/7/4-y) - sin(22/7/4-x)sin(22/7/4-y) =sin(x+y)

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Cos(22/7/4-x) cos22/7/4-y) - sin(22/7/4-x)sin(22/7/4-y) =sin(x+y)

Posted by Abhilasha Chotia 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

We have L.H.S=. {tex}\cos \left( {\frac{\pi }{4} - x} \right)\cos \left( {\frac{\pi }{4} - y} \right)\sin \left( {\frac{\pi }{4} - x} \right){/tex}{tex}\sin \left( {\frac{x}{4} - y} \right){/tex}
{tex} = \cos \left[ {\frac{\pi }{4} - x + \frac{\pi }{4} - y} \right]{/tex}[ {tex}\because {/tex}cos (A+ B) = cos A cos B - sin A sin B]
{tex} = \cos \left[ {\frac{\pi }{2} - (x + y)} \right]{/tex}= sin (x + y) = R.H.S

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