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Cosa\a+cosb\b+cosc\c=a2+b2+c2\2abc

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Cosa\a+cosb\b+cosc\c=a2+b2+c2\2abc
  • 4 answers

Aman Deep Singh Singh 7 years, 4 months ago

Please prove

Nancy Rajput 7 years, 4 months ago

=>cosA/a=b^2+c^2-a^2 /2bc --(1) => cosB/b=a^2+c^2-b^2/2ac-----(2) =>cosC/c=a^2+b^2-c^2 /2ab ----(3) => adding three equation you get a^2+b^2+c^2/2abc

Nancy Rajput 7 years, 4 months ago

its from external exercise

Govind Pandey 7 years, 4 months ago

Please prove that
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