AM is a median of a …

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Sia ? 6 years, 6 months ago
In {tex}\triangle{/tex}ABM
AB + BM > AM....[Sum of the lengths of any two sides of a triangle is greater than the length of the third side].....(1)
In {tex}\triangle{/tex}ACM
CA + CM > AM....[Sum of the lenghts of any two sides of a triangle is greater than the length of the third side].....(2)
Sum (1) and (2)
(AB + BM) + (CA + CM) > AM + AM
{tex}\therefore{/tex} AB + (BM + CM) + CA > 2AM
{tex}\therefore{/tex} AB + BC + CA > 2AM
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