Tan A+CotA=2 than find the valu …

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Sia ? 6 years, 6 months ago
Given, tan A + cot A = 2
We need to square both sides,
(tan A + cot A)2 = (2)2
{tex}\Rightarrow{/tex}tan2A + cot2A + 2 tan A. cotA = 4 {tex}[(a+b)^2=a^2+b^2+2ab]{/tex}
{tex}\Rightarrow{/tex}tan2A + cot2A + 2 tan A{tex}\times \frac { 1 } { \tan A }{/tex}= 4
{tex}\Rightarrow{/tex}tan2A + cot2A + 2 = 4
{tex}\Rightarrow{/tex}tan2A + cot2A = 4 - 2 = 2
Therefore the value of tan2 A + cot2 A = 2
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