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Find the value of k for which the lines (k+1)x + 3ky + 15=0 and 5x +ky +5=0 are coincident

Posted by Akash Joshi 7 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Akshat Makhaik 7 years, 3 months ago

a1/a2=b1/b2=c1/c2 (K+1)/5=3k/k=15/5 Cross ✖ a1/a2&b1/b2 We get K(k+1)=5(3k) K²+k=15k K²-14k=0 K-14=0 K=14 Put value of k K+1/5 15/5 3. 3k/k 42/14 =3 Therefore,a1/a2=b1/b2=c1/c2

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CBSE > Class 10 > Mathematics