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The 8th term of an AP …

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The 8th term of an AP is half of its second term exceeds one third of its fourth by 1.find
  • 1 answers

Satish Kumar 7 years, 3 months ago

a+7d=a+d/2 2a + 14d = a + d a = -13d a +10d = 1/3(a +3d) + 1 a +10d -1 = 1/3(a + 3d) 3(a + 10d -1) = a +3d 3a + 30d -3 = a+ 3d 2a + 27d =3 2(-13d) + 27d =3(since a = -13d) -26d + 27d = 3 d = 3 a= -13d a = -39 a + 14d = -39 + 42 hence a15 =3
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