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In fig the sides AB,BC and CA of ABC touches the circle at P,Q,R respectively.If PA=4,BP=3 AC=11.FIND BC

Posted by Sahil Mandavkar 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

In triangle ABC, we have
BP = BQ = 3cm
AP = AR = 4cm
(tangents drawn from an external point to the circle are equal).
So, RC = AC - AR
= 11 - 4
= 7 cm
Hence RC = CQ = 7 cm
Then, BC = BQ + QC
= 7 + 3
= 10 cm

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