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Prove that (1) (AUB)xC=(AxC)U(BxC)

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Prove that (1) (AUB)xC=(AxC)U(BxC)
  • 2 answers

Uma Shankar Singh Ujjwal 7 years, 3 months ago

So (AUB)×C=(A×C)U(B×C)

Uma Shankar Singh Ujjwal 7 years, 3 months ago

LetA={1,2} and B={3,4} and C={5,6} So (AUB)={1,2,3,4} so (AUB)×C={(1,5),(1,6),(2,5),(2,6),(3,5),(3,6)} (A×C)={(1,5),(1,6),(2,5),(2,6)} And(B×C)={(3,5),(3,6),(4,5),(4,6)} So (A×C)U(B×C)={(1,5),(1,6),(2,5),(2,6),(3,5),(3,6)}
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