The amount of air present in …

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Sia ? 6 years, 6 months ago
Let the volume of the cylinder be 16 litres(a1).
Air removed by pump ={tex}{1 \over 4} \times 16 = 4litres{/tex}
Air present after first removal = 16-4=12 litres(a2)
Air again removed ={tex}{1 \over 4} \times 12 = 3litres{/tex}
Air present after second removal =12-3 =9 litres(a3)
The amount of air present in the cyinder is the series
16,12,9.....
a2-a1= 12-16 = -4
a3-a2=9-12= -3
Since the difference is not same .This is not A.P.
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