No products in the cart.

A particle moves on the xy …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

A particle moves on the xy plane with velocity vx=8t-2 and vy=2. If it passes through the point x=14 and y=4 at t=2s, find the equation (x-y relation) of the path
  • 1 answers

Chirag Solanki 7 years, 4 months ago

As we know y = int. vy dt     and x = int. vdt

                    y = int. 2 dt      and x = int. ( 8t - 2 ) dt

                    y = 2t + c         and x = 8t2/2 - 2t + k

       but  if t = 2 s then y = 4 and x = 14

      so         4 = 4 + c           and    14 = 4x4 - 4 + k

                     c = 0               and    14 = 16 - 4 +k

                                                       k = 2

so y = 2t   and x = 4t2 -2t + 2 

by putting t = y/2 in x

we get x = y2 - y +2             required equation

https://examin8.com Test

Related Questions

Ch 1 question no. 14
  • 0 answers
√kq,qpower2 R2
  • 0 answers
1dyne convert to S.I unit
  • 1 answers
Project report
  • 0 answers
2d+2d =
  • 1 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App