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Find the values of K such …

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Find the values of K such that the quadratic equation. square of x sub 2kx add (7k sub 12)=0 has equal roots

Posted by Nanu Parjapat 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Given equation is {tex}x^2 - 2kx + (7k - 12) = 0{/tex}.
Here {tex}a = 1,\ b = - 2k,\ c = 7k -12{/tex}
{tex}D = b^2 - 4ac{/tex}

{tex}\Rightarrow{/tex}D = (-2k)² - 4 {tex}\times{/tex} 1 {tex}\times{/tex} (7k-12)
= 4k² - 28k + 48
The equation has equal roots, then D = 0
{tex}\Rightarrow{/tex}{tex}4k^2 - 28k + 48 = 0{/tex}

{tex}\Rightarrow{/tex} k² - 7k + 12 = 0

{tex}\Rightarrow {/tex}(k - 3)(k - 4) = 0

{tex}\Rightarrow{/tex} k = 3,4.

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CBSE > Class 10 > Mathematics