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An alternating voltage given by V=110 …

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An alternating voltage given by V=110 sin314t is connected across a pure resistance of 50 Ω, Find the frequency of the source and rms current through the resistance.

Posted by Jagriti Shrey 7 years, 4 months ago

CBSE > Class 12 > Physics

1 answers

H!Mαη$Hμ Ұαδαυ ✔️ 7 years, 4 months ago

It is easy .... Omega =314 rad/s..... _f=314/2π _f=314/2*3.14 _f=50 Hz........ ........and I rms =V rms /R... I rms =110/50 ... I rms=11/5.... I rms=2.2 A

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