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3x*3x+11x+10 by method of completing square

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3x*3x+11x+10 by method of completing square

Posted by Mohammed Saifee 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

The given equation is
{tex}\Rightarrow{/tex} 3x²+11x + 10 = 0
Now, we have to find two numbers such that their sum is 11 and product is 3{tex}\times{/tex}10 = 30. Clearly, 5 +6 =11 and 5{tex}\times{/tex}6 = 30
{tex}\Rightarrow{/tex} 3x²+ 6x + 5x + 10 = 0
{tex}\Rightarrow{/tex} 3x(x + 2) +5(x + 2) = 0
{tex}\Rightarrow{/tex} (3x+5)(x+2) = 0
Either, 3x+5 =0 {tex}\Rightarrow{/tex} {tex}{/tex} {tex}x= - \frac{5}{3}{/tex}
Or, x+2 =0 {tex}\Rightarrow{/tex} x = -2
Hence, the required roots of given equation are -2 and {tex}-\frac{{5}}{3}{/tex}

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