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if x = asec + btan …

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if x = asec + btan and y = atono + bsec Prove that x2 -y2 = a2-b2
  • 1 answers

Sia ? 6 years, 6 months ago

We have,
x = asec{tex}\theta{/tex} + btan{tex}\theta{/tex} and y = atan{tex}\theta{/tex} + bsec{tex}\theta{/tex}
LHS = (x2 - y2) = (asec{tex}\theta{/tex} + btan{tex}\theta{/tex})2 - (atan{tex}\theta{/tex} + bsec{tex}\theta{/tex})2
= (a2sec2{tex}\theta{/tex} + b2tan2{tex}\theta{/tex} + 2absec{tex}\theta{/tex}tan{tex}\theta{/tex}) - (a2tan2{tex}\theta{/tex} + b2sec2{tex}\theta{/tex} + 2absec{tex}\theta{/tex}tan{tex}\theta{/tex})
= a2(sec2{tex}\theta{/tex} - tan2{tex}\theta{/tex}) - b2(sec2{tex}\theta{/tex} - tan2{tex}\theta{/tex})
= a- b2 = RHS
Therefore, LHS = RHS

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