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1root of the equstion 2x square - 8x - m is5/2 find the other root s the value of m

    • Posted by Sumit Kumar 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 5 months ago

    {tex}2x^2 - 8x - m = 0{/tex}
    {tex}\because{/tex}{tex}\frac{5}{2}{/tex} is one root
    2({tex}\frac{5}{2}{/tex})2 - 8{tex}\times{/tex} {tex}\frac{5}{2}{/tex} {tex}- m = 0{/tex} {tex}\Rightarrow{/tex} {tex}\frac{2 \times 25}{4}{/tex} {tex}- 20 - m = 0{/tex}
    {tex}\Rightarrow{/tex}{tex}\frac{25 - 40}{2}{/tex} {tex}- m = 0{/tex} {tex}\Rightarrow{/tex} {tex}\frac{-15}{2}{/tex} = m {tex}\Rightarrow{/tex}m = {tex}\frac{-15}{2}{/tex}.
    Also, sum of roots = -{tex}\frac{b}{a}{/tex} = {tex}\frac{-(-8)}{2}{/tex} = 4
    One root = {tex}\frac{5}{2}{/tex} [given]
    {tex}\therefore{/tex} Other root = 4 - {tex}\frac{5}{2}{/tex} = {tex}\frac{3}{2}{/tex}

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