No products in the cart.

2x/x-3 + 1/2x+3 + 3x+9/(x-3)(2x+3)

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

2x/x-3 + 1/2x+3 + 3x+9/(x-3)(2x+3)
  • 1 answers

Sia ? 6 years, 4 months ago

Given, {tex}\frac{2x}{x-3}+\frac{1}{2x+3}+\frac{3x+9}{(x-3)(2x+3)}=0{/tex}

{tex}\Rightarrow\frac{{2x(2x + 3) + x - 3 + 3x + 9}}{{(x - 3)(2x + 3)}} = 0{/tex}

{tex} \Rightarrow \frac{{4{x^2} + 6x + x - 3 + 3x + 9}}{{2{x^2} + 3x - 6x - 9}} = 0{/tex}

{tex} \Rightarrow \frac{4{x^2} + 10x +6 }{{2{x^2} - 3x - 9}} = 0{/tex}

Cross multiplying equation , we get ,

{tex} \Rightarrow 4{x^2} + 10x +6 = 0{/tex}

{tex} \Rightarrow 4{x^2} + 6x+4x +6 = 0{/tex}

{tex} \Rightarrow x(4{x} + 6)+1(4x +6) = 0{/tex}

{tex}\Rightarrow(x+1)=0{/tex} or {tex} (4x+6)=0{/tex}

{tex}\Rightarrow x=-1{/tex}

{tex}\Rightarrow x=-\frac{3}{2}{/tex}

Hence , the roots of the given quadratic equation are -1 and {tex}-\frac{3}{2}{/tex}

https://examin8.com Test

Related Questions

(A + B )²
  • 1 answers
Venu Gopal has twice
  • 0 answers
sin60° cos 30°+ cos60° sin 30°
  • 2 answers
Find the nature of quadratic equation x^2 +x -5 =0
  • 0 answers
Prove that root 8 is an irration number
  • 2 answers
X-y=5
  • 1 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App