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3k square _k ,d=6 find first …

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3k square _k ,d=6 find first term

Posted by Amanjot Kaur 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Let the sum of k terms of A.P. is S_n = 3k² - k
Now k^th term of A.P = S_n - S_n-1
a_k = (3k² - k) - [3 (k - 1)²- ( k - 1)]
= (3k² - k) - [3 (k²- 2k + 1)- ( k - 1)]
= 3k² - k - [ 3k² -6k + 3 - k + 1]
= 3k² - k - [ 3k² -7k + 4 ]
= 3k² - k - 3k² + 7k- 4
= 6k - 4
first term = a = {tex}6 \times 1 - 4 = 6 - 4 = 2{/tex}

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