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If sin(2x+3y)=1and cos(2x-3y)=root 3÷2..find the value …

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If sin(2x+3y)=1and cos(2x-3y)=root 3÷2..find the value of x and y

Posted by Suhaib Suhaib 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Tanzeela Raaz 7 years, 4 months ago

2x+3y=90. (Sin 90°=1). (1) 2x-3y=√3/2 (cos 30°=√3/2). (2) Solving both the equation, we get 2x+3y=90 2x-3y=30 = 4x=120 = x=120/4 = x= 30 Now, Putting the value of x=30 in (1) 2×30+3y=90 60+3y=90 3y=30 Y=10 Therefore, the value of x=30 and y=10.

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CBSE > Class 10 > Mathematics