Find Sn if an=3+2n

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Sia ? 6 years, 6 months ago
Given, an = 3 + 2n
a1 = 3 + 2{tex}\times{/tex}1 = 5
a2 = 3 + 2{tex}\times{/tex}2 = 7
a3 = 3 + 2{tex}\times{/tex}3 = 9
Thus the series is 5, 7, 9,......in which a = 5 and d = 7 - 5 = 2
{tex}\therefore \quad S _ { n } = \frac { n } { 2 } ( 2 a + ( n - 1 ) d ){/tex}
Sn = {tex}\frac n2{/tex}[2(5) + (n - 1)2]
Sn = {tex}\frac n2{/tex}[10 + 2n - 2]
Sn = {tex}\frac n2{/tex}[8 + 2n]
Sn = 4n + n2
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