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Prove the completing square method. Clearly.

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Prove the completing square method. Clearly.

    • Posted by Piyush Gautam 6 years, 4 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 4 months ago

    {tex}x^2 + 6x - 16 = 0{/tex}
    {tex}\Rightarrow{/tex} {tex}x^2 + 6x = 16{/tex}
    {tex}\Rightarrow{/tex} {tex}x^2 + 6x + 9 = 16 + 9{/tex} [Adding on both sides square of coefficient of x, i.e. ({tex}\frac{6}{2}{/tex})2]
    {tex}\Rightarrow{/tex} {tex}(x + 3)^2 = 25{/tex}
    {tex}\Rightarrow{/tex} x + 3 = {tex}\pm{/tex}{tex}\sqrt{25}{/tex}
    {tex}\Rightarrow{/tex} x + 3  =5 or x + 3 = -5
    {tex}\Rightarrow{/tex} x = 2 or x = -8

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    Posted by Hari Anand 6 months, 1 week ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

    Few rules to keep homework help section safe, clean and informative.
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    CBSE > Class 10 > Mathematics
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