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in the given figure ^a=90°, ^b=90° ob=4.5cm oa=6cm & ad=4cm find qb

Posted by Renuka Mali 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

In {tex}\triangle{/tex}PAO and {tex}\triangle{/tex}QBO
{tex}\angle{/tex}A = {tex}\angle{/tex}B = 90^o
{tex}\angle{/tex}POA = {tex}\angle{/tex}QOB (Vertically Opposite Angle)
{tex}\triangle{/tex}PAO ~ {tex}\triangle{/tex}QBO,(by AA criteria)
{tex}\frac { O A } { O B } = \frac { P A } { Q B }{/tex}
or, {tex}\frac { 6 } { 4.5 } = \frac { 4 } { Q B }{/tex}
or, {tex}Q B = \frac { 4 \times 4.5 } { 6 }{/tex}
Therefore, QB = 3 cm

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CBSE > Class 10 > Mathematics