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The base of an equilateral triangle …

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The base of an equilateral triangle PQR lie on X axis.the coordinates of points q (-4, 0) and origin is the midpoint of the base find the coordinates of P and Q.

    • Posted by Manmohan Singh Lodhi 7 years, 4 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 4 months ago

    Co-ordinates of point R = (4,0)
    {tex}\therefore{/tex} QR = 8 units
    Let the coordinates of point P be (0,y)
    Since, PQ = QR
    or, (-4 - 0)2 + (0 - y)2 = {tex}8^2{/tex}
    or, 16 + y2 = 64
    {tex}y^2=48{/tex}

    or, y = {tex}\pm 4\sqrt 3{/tex}
    Coordinates of P are (0,{tex}4\sqrt3{/tex}) or (0,{tex}-4\sqrt3{/tex})

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