If triangle ABC is similar to …

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Sia ? 6 years, 4 months ago
Given: {tex}\Delta ABC \sim \Delta PQR{/tex}
Since we know that ,the ratio of area of two similar triangles is equal to the square of ratio of their corresponding sides. Thus,
{tex}\frac{\text { ar } \triangle \mathrm{ABC}}{\text { ar } \triangle \mathrm{PQR}}{/tex} = {tex}\frac{\mathrm{AB}^{2}}{\mathrm{PQ}^{2}}{/tex} = {tex}\left(\frac{1}{3}\right)^{2}{/tex} = {tex}\frac{1}{9}{/tex}
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